4.9x^2+25x-42=0

Solution for 4.9x^2+25x-42=0 equation:

4.9x^2+25x-42=0

a = 4.9; b = 25; c = -42;
Δ = b2-4ac
Δ = 252-4·4.9·(-42)
Δ = 1448.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1448.2}}{2*4.9}=\frac{-25-\sqrt{1448.2}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1448.2}}{2*4.9}=\frac{-25+\sqrt{1448.2}}{9.8}
$